Math, asked by mgulamkasam, 6 months ago

A store purchase 50 case of soap at Rs 30.
first 35 case sold at Rs. 50.
remaining were mark down to10% less than cost price and sold it.
how did process from sales the soap compare with cost?​

Answers

Answered by feminasikkanther
2

Answer:

Process from sales the soap compare with cost = 43.667 %

Step-by-step explanation:

Quantity of Soap cases = 50 cases

Price of cost = 30 ₹

Total price of cost = 50×30 ₹ = 1500 ₹

For first 35 cases of soap

Price of selling = 50 ₹

Total price of selling = 1750 ₹

For remaining 15 cases of soap

Price of selling = 10% less than cost price

10\% \: less \: than \: 30 \\  = 30 - (30 \times  \frac{10}{100} ) \\  = (30 - 3)  \: ₹ \\   = 27 \: ₹

Total price of selling = 15 × 27 ₹ = 405 ₹

So, Grand Total price of selling

= 1750+405 ₹

= 2155 ₹

So, Total Profit = (2155 - 1500) ₹ = 655 ₹

Total Profit (%) ;

profit  = (100 \times  \frac{655}{1500 \\})\%  \\  = 43.667\%

Answered by sureeshravi
1

Answer: The sales proceeds are much higher than the actual cost of acquiring the cases, generating a profit of Rs.655 for the shop.

Step-by-step explanation:
No of soap cases purchased= 50
Cost Price of each case= Rs.30
∴ Total cost price of purchasing 50 soap cases
= 50×30
= Rs.1500

According to question,
First 35 cases were sold for Rs 50
∴ Total revenue from selling 35 cases
= 35×50
= Rs.1750

Now, remaining soap cases were sold at a price 10% less than the cost price
∴ Selling price for 15 cases
= 30-\frac{10}{100}×30
= Rs.27
∴ Total revenue from selling 15 cases
= 15×27
= Rs.405

Total revenue earned from selling 50 soap cases
= 1750+405
= Rs.2155

Profit= 2155-1500
= Rs.655

Thus, the proceeds from sales of the soap cases were much higher than the actual cost, generating a profit of Rs.655 for the shop.

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