Question

A store sells the basic model of a phone for $60 and the upgraded model for $200. It costs the store $10 to buy each basic model and $50 to buy each upgraded model from the phone company. On Tuesday, the store has $1,800 in sales for these two models, and it paid the phone company $400 to buy these phones. How many upgraded models did the store sell on Tuesday?

Answer 1

Step-by-step explanation:

Let x = no. of basic model

Let y = no. of upgraded model

Sales : 60x + 200y =1800 .......(I)

Purchase : 10x + 50 y = 400.........(ll)

from equation (1) & (2)

60x+200y-1800=0

10x+50y -400 =0

- - +

————–————————

50x+150y-1400=0..........(3)

...........25x+75y-700=0

20x=200

x=200/20

x =10

10(x)+50y=400

10(10)+50y=400

100+50y=400

50y=400-100

y=300/50

y=6

Answer 2

Given: Basic model of phone sold for $60, upgraded model sold for $200. Cost to the store is $10 for each basic model and $50 for each upgraded model. Store sales is $1,800, cost is $400.

To find: Number of models sold.

Solution:

• Let x be the number of basic models sold and let y be the number of upgraded models sold.

• According to the sales, $60 is the selling price for the basic model, $200 is the selling price of the upgraded model and the total sale of the store on Tuesday is $1800.

• Hence, $60x +200y = 1800$.

• According to the costs, $10 is the cost price for the basic model, $50 is the cost price of the upgraded model and the total cost to the store on Tuesday is $400.
• Hence, $10x +50y = 400$.
• When the equations are solved simultaneously, it is found that,

        $x = 10$ and $y = 6$

• Here, y is the number of upgraded models sold.

Therefore, 6 upgraded models were sold by the store on Tuesday.