Question

A storege room is 6 m long, 5 m wide and 3.5 m high . how many tanks of capacity 120 litres each ,can it hold?

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\pink{\:\:\:\:\:\:\:Given:-\:\:\:\:\:\:\:}}$

$\sf\bullet\:\:\: Dimensions\:of\:room\\ \\ \sf\implies 6m\times 5m\times 3.5m$

• Now we have to find the Volume of room

$\boxed{\sf{Volume\:of\:cuboid=length\times breadth\times height}}$

$\bf\underline{\underline{\red{\:\:\:\:\:A.T.Q\:\:\:\:\:\:}}}$

$\sf:\implies Volume=6\times 5\times 3.5\\ \\ \sf:\implies 30\times 3.5\\ \\ \sf:\implies 105.0m{}^{3}$

Now Convert Cubic.metre into litres

$\sf\underline{\bullet 1m{}^{3}=1000litres}$

$\sf:\implies 105m{}^{3}=105\times 1000\\ \\ \sf:\implies 105000litres$

• Now we have have to find how many tanks of capacity 120 litre this box can hold

$\boxed{\sf{No.\:of\:tanks\:it\:can\: hold=\dfrac{Capacity\:of\:room}{Capacity\:of\:tank}}}$

$\sf:\implies No.\:of\: tanks=\dfrac{1050\cancel0}{12\cancel0}\\ \\ \sf:\implies No.\:of\:tanks=\cancel{\dfrac{10500}{12}}\\ \\ \sf:\implies No.\:of\:tanks=875$

$\boxed{\sf{No.\:of\: tanks\:it\:can\:hold=875}}$

Answer 2

$\huge\color\red{\:\: SOLUTION\:\:}}$

$given \: dimensions \: =》 6m \times 5m \times 3.5m \\ \\ volume \:=》 \: length \times \: breadth \times height \\ volume \\ =》 6 \times 5 \times 3.5 {m}^{3} \\ = 105 {m}^{3} \\ \\ \\ we \: know \\ 1 {m}^{3} =》 1000 \: lit \\ then \\ 105 {m}^{3} \\ = 1000 \times 105lit \\ \\ = 105000 \: liters$

$Number\: of\: tanks\\=》105000÷120\\=875$