Question

A storekeeper has 3 types of shirts. 16 yellow, 12 green and 10 blue. if sold 3 shirts, what is the probability that these are either all yellow or green

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer: The required probability is $\dfrac{65}{703}$

Step-by-step explanation:

Since we have given that

Number of yellow shirts = 16

Number of green shirts = 12

Number of blue shirts = 10

We need to find the probability of getting 3 shirts either yellow or green.

Number of shirts drawn = 3

According to question, we get that

$\dfrac{^{16}C_3}{^{38}C_3}+\dfrac{^{12}C_3}{^{38}C_3}\\\\=\dfrac{560}{8436}+\dfrac{220}{8436}\\\\=\dfrac{560+220}{8436}\\\\=\dfrac{780}{8436}\\\\=\dfrac{65}{703}$

Hence, the required probability is $\dfrac{65}{703}$