Math, asked by prabhashmishra711, 8 months ago

A storekeeper has 3 types of shirts. 16 yellow, 12 green and 10 blue. If he sold 3
shirts, what is the probability that these are either all yellow or green?

(a) 25/126
(b) 135/703
(c) 65/1375
(d) 23/65
(e) 65/703

Answers

Answered by jay272
2

Answer:

none of the following it's answer will be 3 / 38

mark as brainlesy

Answered by windyyork
0

Option 'e' is correct.

Step-by-step explanation:

Since we have given that

Number of yellow shirts = 16

Number of green shirts = 12

Number of blue shirts = 10

So, the probability of getting either yellow or green out of 3 shirts is given by

P(yellow) + P(Blue)

\dfrac{^{16}C_3}{^{38}C_3}+\dfrac{^{12}C_3}{^{38}^C_3}\\\\=\dfrac{560}{8436}+\dfrac{220}{8436}\\\\=\dfrac{560+220}{8436}\\\\=\dfrac{780}{8436}\\\\=\dfrac{260}{2182}\\\\=\dfrac{130}{1406}\\\\=\drac{65}{703}

Hence, Option 'e' is correct.

# learn more:

A, B, C and D are four friends each of whom wear a shirt of different colour among – Red, White, Green and Yellow. C wear neither Red nor White shirt. B wear either Yellow or Red shirt. If D wears Green shirt, then what is the colour of A’s shirt?

(A) White

(B) Yellow

(C) Red

(D) Either A or B

https://brainly.in/question/6343362

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