Question

A storm broke a tree and the treetop rested 20 m from the base of the tree, making an angle of 60° with the horizontal. Find the height of the tree.

Answer 1

Final Answer :
$(\frac{40}{ \sqrt{3} } + 20)m$

Steps:
1) Let the height of the slant part of tree be x.
Then, By Trigonometry.

$\sin(60 \degree) = \frac{20}{x} \\ = > \frac{ \sqrt{3} }{2} = \frac{20}{x} \\ = > x = \frac{40}{ \sqrt{3} } m$

Therefore, Total initial height of tree is
$(20 + \frac{40}{ \sqrt{3} } )m$

Answer 2

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