Question

A storm caused a tree to fall from a height of 6m above the ground. The

two parts of the tree did not separate and the tree top touches the ground

at a distance of 8m from its base. What was the actual height of the tree?
​

Answer 1

Answer:

16 m

Step-by-step explanation:

We are given that a tree is broken at a height of 6 m from the ground

So, Right triangle is formed

So. Perpendicular = 6 m

Its top touches the ground at a distance of 8 m from the base of the tree.

So, Base = 8 m

hypotenuse ^2 =   base^2 + perpendicular^2

h^2 = 64 + 36

h = √100

h = 10

hypotenuse is the length of the tree broken out

Original height = 10+6 = 16 m

Hence the original height of tree is 16 m

please mark it as brainliest

Answer 2

the perpendicular = 6 cm

the base = 8 cm

according to questions we have to find the total length of tree

so, first we have to find broken length and then we have to add the perpendicular to find actual length

so finding the length of broken length

h^2 = b^2 + p^2. ( by putting Pythagoras theorem)

h = √8^2 + 6^2

h = √64+36

h= √100

h = 10

hypotenuse= 10 but

actual length = 10 cm + 6 cm

16 cm

thus 16 cm is ans