A storybook begins from page 1 to page 233. How many times does the digit ‘2’ appear on all the page numbers?
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Answered by
4
Hey !!
Here is your answer....
➡ Given :- Storybook has 233 pages total.
➡ To Find :- How many times 2 appears on all page numbers.
➡ Solution :- ' 2 ' appears between 1 - 100 no. pages.
↪ ( 2, 12, 22, 32, 42, 52, 62, 72, 82, 92 ) = 10
↪( 20, 21, 22, 23,..... 29 ) = 10
↪ Total = 20 --------( 1 )
' 2 ' appears between 101 - 200 no. of pages.
↪ ( 102, 112, 122, 132, 142, 152, 162,.... 192 ) = 10
↪ ( 120, 121, 122, 123, 124, .....129 ) = 10
↪( 200 ) = 1
↪ Total = 21 ---------( 2 )
' 2 ' appears between 201 - 233 no. of pages.
↪ ( 201......233 ) = 33
↪ ( 202, 212, 232 ) = 3
↪( 221, 222, 223, 224, ....... 229 ) = 9
↪ ( 220 ) = 1
↪ Total = 46 ----------( 3 )
Now add eq. ( 1 ) , ( 2 ) and ( 3 )
= 20 + 21 + 46
= 87
so, 87 times digit ' 2 ' is appears on page no.
1 to 233.
HOPE IT HELPS YOU..
THANKS ^-^
Here is your answer....
➡ Given :- Storybook has 233 pages total.
➡ To Find :- How many times 2 appears on all page numbers.
➡ Solution :- ' 2 ' appears between 1 - 100 no. pages.
↪ ( 2, 12, 22, 32, 42, 52, 62, 72, 82, 92 ) = 10
↪( 20, 21, 22, 23,..... 29 ) = 10
↪ Total = 20 --------( 1 )
' 2 ' appears between 101 - 200 no. of pages.
↪ ( 102, 112, 122, 132, 142, 152, 162,.... 192 ) = 10
↪ ( 120, 121, 122, 123, 124, .....129 ) = 10
↪( 200 ) = 1
↪ Total = 21 ---------( 2 )
' 2 ' appears between 201 - 233 no. of pages.
↪ ( 201......233 ) = 33
↪ ( 202, 212, 232 ) = 3
↪( 221, 222, 223, 224, ....... 229 ) = 9
↪ ( 220 ) = 1
↪ Total = 46 ----------( 3 )
Now add eq. ( 1 ) , ( 2 ) and ( 3 )
= 20 + 21 + 46
= 87
so, 87 times digit ' 2 ' is appears on page no.
1 to 233.
HOPE IT HELPS YOU..
THANKS ^-^
KunalTheGreat:
tnx
Answered by
2
heya mate
here is your answer
☆ 1st lets count from 1 to 100
(2,12,22,32,42,52,62,72,82,92)
hey dude don't forget to count..... like me
( 20,21,23,24,25,26,27,28,29)
well total numbers we have found are nearly not exactly 11+9 = 20
and count from 100 to 200
(102, 112,122,132,142,152,162,172,182,192 )
here 12 are there
becoz in 122 there are 2digts
ooo still we have
( 120,121,123,124,125,126,127,128,129) = 9
total = 12+9 = 21
now from 200 to 223
( 201,202,203,204.......209) = 10
(210,211,212,213,214......219) = 10
(220,221,222,,,,,229)= 21
(230,231,232,233) = 5
so total = 46
now add all the totals
20+21+46= 87
i hope it helped u
thanks !!!
here is your answer
☆ 1st lets count from 1 to 100
(2,12,22,32,42,52,62,72,82,92)
hey dude don't forget to count..... like me
( 20,21,23,24,25,26,27,28,29)
well total numbers we have found are nearly not exactly 11+9 = 20
and count from 100 to 200
(102, 112,122,132,142,152,162,172,182,192 )
here 12 are there
becoz in 122 there are 2digts
ooo still we have
( 120,121,123,124,125,126,127,128,129) = 9
total = 12+9 = 21
now from 200 to 223
( 201,202,203,204.......209) = 10
(210,211,212,213,214......219) = 10
(220,221,222,,,,,229)= 21
(230,231,232,233) = 5
so total = 46
now add all the totals
20+21+46= 87
i hope it helped u
thanks !!!
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