Question

A stove element draws 15a when connected to a 120 v line. How long does it take to consume 30 kj?

Answer 1

current 'I' = 15A
volt V = 120v
using P = VI
P = 120 × 15
P = 1800watt
now work done is given 30 kj
using
workdone = P × t
W = 1800 × t
30 × 1000 j = 1800 × t
t = 16.67 sec
it take 16.67 second to consume 30kj

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Answer 2

Answer:

Time, t = 16.66 seconds

Explanation:

Given that,

Current, I = 15 A

Voltage, V = 120 volts

Energy, E = 30 kJ

Let t is the time taken.

The energy used is given by :

$E=P\times t$

And the power is given by :

$P=I\times V$

$t=\dfrac{E}{VI}$

$t=\dfrac{3\times 10^4}{120\times 15}$

t = 16.66 seconds

So, the stove will take 16.66 seconds. Hence, this is the required solution.