A stove element draws 15a when connected to a 120 v line. How long does it take to consume 30 kj?
Answers
Answered by
42
current 'I' = 15A
volt V = 120v
using P = VI
P = 120 × 15
P = 1800watt
now work done is given 30 kj
using
workdone = P × t
W = 1800 × t
30 × 1000 j = 1800 × t
t = 16.67 sec
it take 16.67 second to consume 30kj
I HOPE IT IS HELPFUL TO YOU☺☺☺
volt V = 120v
using P = VI
P = 120 × 15
P = 1800watt
now work done is given 30 kj
using
workdone = P × t
W = 1800 × t
30 × 1000 j = 1800 × t
t = 16.67 sec
it take 16.67 second to consume 30kj
I HOPE IT IS HELPFUL TO YOU☺☺☺
Answered by
17
Answer:
Time, t = 16.66 seconds
Explanation:
Given that,
Current, I = 15 A
Voltage, V = 120 volts
Energy, E = 30 kJ
Let t is the time taken.
The energy used is given by :
And the power is given by :
t = 16.66 seconds
So, the stove will take 16.66 seconds. Hence, this is the required solution.
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