a straght line through Q (√3, 2)markas an angle f\6 whith positive direction of the x axis in the straight line intersects the line √3x-4+8=0at find distance
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03-Oct-2019 · 1 answer
Given, straight line (2) and the straight line √3x-4y+8 =0 . ... Now, by {(4)-( 3)}, we get, y-5 =0, ⇒y=5 ... So, point q becomes (4√3, 5). Hence, the distance pq= = = 6 units.
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