Question

A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of 0.9 Wb/m². The induced e.m.f. across the conductor will be(a) 7.25 V(b) 3.75 V(c) 1.25 V(d) 2.52 V

Answer 1

Correct Answer is d: 2.52 V

Explanation :

length=0.4m

speed = v= 7m/s

B=0.9 weber/meter ²

Formula :

e=BVl

=0.9x7x0.4

=2.52 Volts

∴ The induced e.m.f. across the conductor will be 2.52 volts

Answer 2

$\huge\mathfrak\pink{Answer}$

l = 0.4 m

v = 7 m/s

B = 0.9 wb/m²

e = Bvl => 2.52 V answer

$\huge\mathcal\orange{hope\:it\:helps}$ ❤