A straight current carrying conductor 30cm long carries a current of 5A . It is placed in a uniform magnetic field of induction 0.2 T with its length making an angle of 60° with the direction of the field find the force acting on the conductor.
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Answer:
• The force acting on the conductor is 0.2598
Explanation:
Given :
• Length of conductor = 30 m = 0.3 m
• Current(I) = 5A
• Uniform magnetic field(B) = 0.25
• Angle of magnetic field (O) = 60°
To Find :
The force acting on the conductor (F)
Solution :
F = I (B × I)
F = I. B. L. sinO
= 5 × 0.2 × 0.3 × sin 60°
= 0.3 × √3/2
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Explanation:
A straight current carrying conductor 30cm long carries a current of 5A . It is placed in a uniform magnetic field of induction 0.2 T with its length making an angle of 60° with the direction of the field find the force acting on the conductor.
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