Question

A straight current carrying conductor, 30cm long carries a current of 5A, It is placed in a uniform magnetic field of induction 0.2 T, with its length making an angle of 60° with the direction of field. Find the force acting on the conductor.

Answer 1

hope it will help you

Answer 2

NET FORCE EXPERIENCED BY CONDUCTOR IS 0.26 NEWTON.

Given:

• Current = 5A
• Length = 30 cm = 0.3 m
• Magnetic field intensity = 0.2 T
• Angle = 60°

To find:

• Net force experienced by conductor?

Calculation:

The general expression of force experienced by a current carrying conductor placed in a magnetic field is as follows :

$F = i \times L \times B \times \sin( \theta)$

$\implies F = 5 \times 0.3 \times 0.2 \times \sin( {60}^{ \circ} )$

$\implies F = 5 \times 0.3 \times 0.2 \times \dfrac{ \sqrt{3} }{2}$

$\implies F = 5 \times 0.3 \times 0.1\times \sqrt{3}$

$\implies F \approx 0.26\: N$

So, net force experienced by the conductor is approximately 0.26 N.