Question

A straight highway leads to foot of the tower a man standing on the top of the tower observes a car at an angle of depression of 30 degree which is approaching the foot of the tower with uniform speed 6 seconds later the angle of depression of car is found to be 60 degree find the time taken by the car to reach the foot of the tower from from this.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Let the distance traveled by the car in 6seconds=AB=X metres

Height of the tower CD=h metres

The remaining distance to be traveled by the car BC =d metres

AC =AB+BC=x+d metres

ANGLE PDA=ANGLE DAC=30

ANGLE PDB=ANGLE DB*C=60

TRIANGLE BCD TAN60=CD/BC=root3=h/d

h=root3d

TRIANGLE ACD TAN30=CD/AC

1/root3=h/(x+d)

h=(x+d)/root3

(x+d)/root3=root3d

x+d=3d

x=2d

d=x/2