Question

a straight highway leads to the foot of 50 m tall tower from the top of the tower the angle of depression of two cars on the highway are 30 and 60 what is the distance between two cars and how far is rich car from the tower

Answer 1

here's your answer looking for ______

↪Let AB be the tower of height 50 m.

↪Let C and D be the position of the 2 cars.

Let ∠ADB = 60° 

and ∠ACB = 30°

↪In ∆ABD.

tan 60° = AB / BD

=》 under root 3 = 50 / BD

BD = 50 / under root 3

=》50 underroot 3 /3

=》50 ×1.732 / 3

= 86.6 / 3 = 28.86m.

In triangle ABC ,

Tan 30° = AB / BC

=》 1 / underroot 3 = 50/BC

=》 BC = 50 underroot 3 = 86.6 m.

↪so , the distance of the first car from the tower =》28.86m

↪distance of second car = 86.6m

___________⭐⭐⭐

hope it helps ...

be brainly

Answer 2

Hi there

Here's your answer

Hope it helps