A straight highway leads to the foot of a national communication and telecasting tower. A watchman standing at the top of the tower observes a car at an angle of depression of 30 which is approaching the foot of the tower with a uniform speed. 2 minutes later the angle of depression was found to be 60 degree. Then the watchman suspects that some terrorist are approaching the tower. It needs half a minute for the watchman to inform the security staff to be on the alert . How much time the car will take to reach the foot of the tower
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Now consider the triangle ,ABD
tan 30° = AB/BD
1/√3 =AB / BD
BD/ √3 = AB
BC + CD /√3 + AB....(1)
In Δ ABC
tan 45° = AB/BC
1 = AB/BC
AB =BC ..(2)
substitute the value of BC from equation (1) & (2)
Ab + CD/ √3 =Ab
Ab + CD =√3 AB
√3 AB -AB =CD
AB (√3 -1) = CD...(3)
The car takes 12 min to cover the distance CD
CD= 12v...(4)
Putting the value of CD in equation (4)
AB (√3-1) = 12v
AB (√3 -1)/12 = v...(5)
time taken by the car to cover the distance BC
Time = Distance / Speed
Time = BC/ AB (√3 -1 )
Time = 12 AB / AB (√3-1)
Time = 12 / √3-1
≈ 16.4 minutes
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