A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an a
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The whole question is:
a straight highway leads to the foot of a tower. a man standing at the top of the tower observes a car at an angle of depression of 30 degree, which is approaching the foot of the tower with a uniform speed. 6 seconds later, the angle of depression of the car is found to be 60 degree. find the time taken by the car to reach the foot of the tower from this point?
Step-by-step explanation:
Let OA be the tower of height h, and P be the initial position of the car when the angle of depression is 30º.
After 6 seconds, the car reaches to Q such that the angle of depression at Q is 60º. Let the speed of the car be v, meter per second. Then,
PQ=6v (Distance = speed x time)
and let the car take t seconds to reach the tower OA from Q (Fig. 11.39). Then, OQ =vt meters.
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