Question

A straight highway leads to the foot of the tower ,a man standing at the top of the tower observed a car at the angle of depression of 30 degree, which is approaching the foot of the tower with uniform speed .6 second later, the angle of depression of the car is found to be 60 degree. Find the time taken by the car to reach the foot of the tower from this point.

Answer 1

time taken by car will be 9 seconds
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Answer 2

let A be the position of car when angle of depression from the top C of tower CD is 30 degree and B be the position after 6s when angle of depression is 60 degree

let h be the height of tower

a/q <xca=30 ,<xcb=60 (angle of depression

<cad=<xca=30 ,<cbd=<xcb=60(alternate angles)

distance travelled by car A to B in 6s

AB=v*6=6v(d=v*t)

BD=v*t(t= time taken to reach D from B with uniforn speed V)

next step is in the attachment