Question

A straight highway leeds to the foot of the tower. A man Standing at the top of the tower observes a car at an angle of depression of 30degree which is approaching the foot of the tower with a unform speed. six secods later, the angle of depression of the car is found to be 60degree,find the time taken by the car to reach the foot of the tower from this point.

Answer 1

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Answer 2

SOLUTION

Let C and D be the two points of the car and AB be the tower

Let C and D be the two points of the car and AB be the towerLet speed of the car = v unit/sec.

In ∆ABC,

=) tan 60° = AB/BC

=) √3= y/x

=) y= √3x........(1)

Also, In ∆ABD,

=) tan 30° = AB/BD

=) 1/√3= √3x/x+ 6v

=) x= 3v

=) Hence,

Required time =} distance/speed

=) BC/v

=) x/v seconds

=) 3v/v = 3 seconds

hope it helps ✔️