Question

A straight, how wire carries a current of 20 A. Another wire carrying equal current is placed parallel to it. If the force acting on a length of 10 cm of the second wire is 2.0 × 10−5 N, what is the separation between them?

Answer 1

Given:

Magnitude of current in both wires, i1 = i2 = 20 A

Force acting on 0.1 m of the second wire, F = 2.0 × 10−5 N

∴ Force per unit length = 2×10−50.1 = 2.0 × 10−4 N/m

Now,

Let the separation between the two wires be d.

Thus, the force per unit length is given by

 Fl=μ0i1i22πd⇒2.0×10−4=2×10−7×20×20d⇒d=0.4 m=40 cm

Answer 2

Answer:

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