Question

A straight line cuts the coordinates axis at a and b .if the mid point of ab=(2,3) then find the equation of ab

Answer 1

Answer:

6x-4y-24=0

Step-by-step explanation:

The formula with the values placed in will be

(y-0)/(0-b)=(x-a)/(a-0)

You can also find out slope and use the slope intercept form y=mx+c if you want, it's all the same.

Hope it helps mate

Answer 2

Answer:

The equation of ab is  3x + 2y − 12=0.

Let, x−intercept be a

      y−intercept be b

The coordinate of A is (a,0) and the coordinate of B is (0,b)

Midpoint of AB= ( $(x_{1} +x_{2})/2$ , $(y_{1} + y_{2}) /2$

(2,3)=( a+0/2 , 0+b/2 )

by comparing them

2 = a/2

3 = b/2

a = 4, b = 6

Intercept form of line :

x/a + y/b = 1

x/4 + y/6 = 1

(3x + 2y)/12 = 1​

3x+2y = 12

Therefore, The equation  is 3x + 2y − 12=0

Know more about the Equation of line here:

https://brainly.in/question/2251170

Know more about coordinates here:

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