Question

A straight line is drawn joining the points (3, 4) and (5,6). If the line is extended, the ordinate of the point on the line, whose abscissa is –1 is

Answer 1

A(3,4)
B(5,6)
therefore the line is
x - y + 1 = 0
substituting x = -1
-1 - y = 0
-y = 1
y = -1

Answer 2

The ordinate of the point which passes through (3,4) and (5,6) and with abscissa -1 is 0.

• A straight line is drawn joining the points (3,4) adn (5,6).
• We have to find the ordinate of the point  whose abscissa is -1, we have to find the ordinate of the point.
• To find the ordinate, we first find the equation of line passing through the points.
• Equation of line in two point form is

$\frac{y-y_1}{x-x_1}$ = $\frac{y_2-y_1}{x_2-x_1}$

where, $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.

• Now , Equation of line passing through (3,4) and (5,6) is $\frac{y-4}{x-3}$ = $\frac{6-4}{5-3}$.

y - 4 = x - 3

x - y + 1 = 0

• Now the point whose abscissa is -1 passes through this line, we have to find the ordinate.

-1 - y + 1 =0

y = 0.

• The ordinate of the point whose abscissa is -1 is 0.