A straight line l passing through point (3,-2) inclined at an angle of 60 degree to the line root3x + y = 1. If l also intersecs x-axis then the equation of line l is
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Answer:
y = √3x (or) y = 0
Step-by-step explanation:
ɢɪᴠᴇɴ ᴛʜᴀᴛ ᴛʜᴇ ʟɪɴᴇ ᴘᴀꜱꜱᴇꜱ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴏʀɪɢɪɴ. ꜱᴏ, ɪᴛꜱ ᴄᴏᴏʀᴅɪɴᴀᴛᴇꜱ ᴡɪʟʟ ʙᴇ ᴏ(0,0)
ꜱʟᴏᴘᴇ ᴏꜰ ᴛʜᴇ ɢɪᴠᴇɴ ʟɪɴᴇ: √3x + ʏ = 1 ɪ.ᴇ ᴍ₁ = -√3.
ʟᴇᴛ ᴛʜᴇ ꜱʟᴏᴘᴇ ᴏꜰ ᴛʜᴇ ʀᴇQᴜɪʀᴇᴅ ʟɪɴᴇ ᴡʜɪᴄʜ ᴍᴀᴋᴇꜱ 60° ᴡɪᴛʜ ᴀʙᴏᴠᴇ ʟɪɴᴇ ɪꜱ ᴍ.
∴ ᴛᴀɴ 60° = |-√3 - ᴍ/1 - √3ᴍ|
⇒ √3 = |-√3 - ᴍ/1 - √3ᴍ|
⇒ -√3 - ᴍ = √3 - 3ᴍ (ᴏʀ) -√3 - ᴍ = -√3 + 3ᴍ
⇒ ᴍ = √3 (ᴏʀ) ᴍ = 0
ɢɪᴠᴇɴ ᴛʜᴀᴛ ʟɪɴᴇ ɪꜱ ᴘᴀꜱꜱɪɴɢ ᴛʜʀᴏᴜɢʜ (0,0).
ʜᴇɴᴄᴇ, ᴛʜᴇ ᴇQᴜᴀᴛɪᴏɴ ꜰᴏʀ ᴛʜᴇ ʀᴇQᴜɪʀᴇᴅ ʟɪɴᴇ ɪꜱ:
⇒ ʏ + 0 = √3(x - 0) (ᴏʀ) ʏ + 0 = 0(x - 0)
⇒ ʏ = √3x (ᴏʀ) ʏ = 0
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ!
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