a straight line meets the coordinates axes at a and b so that the centroid of the triangle OAB is (1,2). Then the equation of the line AB is.. PLEASE ANSWER QUICKLY AND NO SPAMS PLEASE.
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Step-by-step explanation:
Given a straight line meets the coordinates axes at a and b so that the centroid of the triangle OAB is (1,2). Then the equation of the line AB is
- Now from line AB we have x/h + y/k = 1
- If we plot a graph we have centre to be (0,0) and a line AB with coordinates (0, k) and (h,0)
- So centroid G = (x1 + x2 + x3 / 3 , y1 + y2 + y3 / 3)
- So we have G = (0 + h + 0 / 3 , 0 + 0 + k / 3)
- So centroid G = (h/3, k/3)
- So this (h/3, k/3) = (1,2)
- So h/3 = 1 or h = 3
- Also k/3 = 2
- Or k = 6
- So we have x/h + y/k = 1
- Or x/3 + y/6 = 1
- Or 2x + y / 6 = 1
- Or 2x + y = 6
- Therefore the equation of the line AB is 2x + y = 6
Reference link will be
https://brainly.in/question/7193277
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