Question

a straight line meets the coordinates axes at a and b so that the centroid of the triangle OAB is (1,2). Then the equation of the line AB is.. PLEASE ANSWER QUICKLY AND NO SPAMS PLEASE.

Answer 1

Step-by-step explanation:

Given a straight line meets the coordinates axes at a and b so that the centroid of the triangle OAB is (1,2). Then the equation of the line AB is

• Now from line AB we have x/h + y/k = 1
• If we plot a graph we have centre to be (0,0) and a line AB with coordinates (0, k) and (h,0)
• So centroid G = (x1 + x2 + x3 / 3 , y1 + y2 + y3 / 3)
• So we have G = (0 + h + 0 / 3 , 0 + 0 + k / 3)
• So centroid G = (h/3, k/3)
• So this (h/3, k/3) = (1,2)
•   So h/3 = 1 or h = 3
• Also k/3 = 2
• Or k = 6
• So we have x/h + y/k = 1
•            Or x/3 + y/6 = 1
•         Or 2x + y / 6 = 1
•          Or 2x + y = 6
• Therefore the equation of the line AB is 2x + y = 6

Reference link will be

https://brainly.in/question/7193277