a straight line passes tbrough the point (1, -4) and makes an angle 60° with the positive direction of x- axis ,find the equation of the
straight line
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Answer:
√3 x-y-4-√3 =0
Step-by-step explanation:
The equation of a lin is:
y=mx+c
here m=tan 60°=√3
y=√3 x +c
This line passes through(1,-4)
Thus -4=√3 *1+c
c=-4-√3
Thus the equation becomes
y=√3 x-4-√3
Or √3 x-y-4-√3 =0
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