Question

A straight line passes through the points (2, 4) and (-1, - 5). Find its equation.​

Answer 1

Answer:

First we work out the gradient, which is rise/run = (4- -5)/(2- -1) = 9/3 = 3

Then we quote the formula y - y₁ = m(x - x₁) so y - 4 = 3(x - 2)

Multiplying out brackets gives y - 4 = 3x - 6

This simplifies to y = 3x - 2

Answer 2

Step-by-step explanation:

The points of a line (–1, –5) and (2,4) are given

Then,as we know that

If two points of a line are given

Then equation of a line written as slope form.

(y–y1)/(x–x1)=(y2 –y1)/(x2–x1)

=>{y–(-5)}/{x–(-1)}={4–(-5)}/{2–(-1)}

=>(y+5)/(x+1)=(4+5)/(2+1)

=>(y+5)/(x+1) =9/3

=>(y+5)/(x+1)=3

=>y+5=3(x+1)

=>y+5=3x+3

=>y–3x +5–3=0

y–3x +2 =0

Therefore y–3x +2 =0 is required equation of a line