a straight line passes through two points with co ordinates 6,8 0,5
Answers
Step-by-step explanation:
A straight line passes through 0,6 and has a gradient of -2. It intersects the line with equation of 5x-8y-15 at point p. What are the coordinates of P?
A straight line passes through 0,6 and has a gradient of -2. It intersects the line with equation of 5x-8y-15 at point p. What are the coordinates of P?
Repeat after me: 5x−8y−15 IS NOT AN EQUATION!
It’s an expression. It is critically missing anything indicating that there are two values equal to each other.
As such, it is not the equation of a line.
In order to answer your question, I have to guess at what you meant by “the line with equation of 5x−8y−15 ". Two reasonable guesses are that you meant the line with the equation 5x−8y=15 , the line with the equation 5x−8y−15=0 (which is the same line), or the the line with the equation 5x−8y=−15 . In other words, I have guess where the missing equals sign goes.
So, given that, let’s take a look at the straight line you have.
The general equation for a line is ax+by=c , and it has a gradient of −ab . Since your line has a gradient of −2 , we can assume that b=1,a=−2 and work out what an appropriate value for c is. So we have −2x+y=c , and we know that x=0,y=6 is a solution. That gives us −2(0)+6=c , or c=6 . The equation of your line is −2x+y=6 .
So now you have two simultaneous linear equations in two variables. As long as they don’t have the same gradient — as long as they aren’t parallel — there will be a unique solution. That should be easy for you to solve.