Question

A straight line through the point (2,2) intersects the line √3x+y=0 aand√3x−y=0 at the point A and B. The equation to the line AB so that the triangle OAB is equilateral, is ​

Answer 1

Step-by-step explanation:

line passes through (2, 2) & intersects line √3x + y = 0 and √3x – y = 0 at point A and B.

∴ slope of line y = – √3x is tanθ = – √3

∴ line makes tan–1(– √3) = 120° with OX. also slope of line y = √3x is tanθ = √3

∴ line makes tan–1(√3) = 60° with OX.

∴ equation of line is y = 2.