Question

a straight line whose slope is not defined,passes through the point of intersection of the lines x-3y+2=0 and 2x+5y-7=0 and perpendicular to the line 3x+2y+5=0 is​

Answer 1

Answer:

22x + 33y + 17 = 0

Step-by-step explanation:

let the slope of line be m_1

Given line perpendicular to it is

3x + 2y + 5 = 0

y = -(3/2)x-(5/2)

slope of this line = -(3/2)

now m_1×(-(3/2)= -1

m_1 = 2/3

Now point of passage is PI of

x - 3y + 2= 0 and 2x + 5y - 7 =0

Now

x = 3y - 2

sub in other equation

2 (3y - 2) + 5y - 7 = 0

11y - 9 = 0

y = 9/11

x = 5/11

Now the line is

y - 9/11 =(2/3)×(x - 5/11)

33y - 27 = 22x - 10

22x + 33y + 17 = 0

is the required line.

HOPE IT HELPS