Question

A straight pole of 6cm castes a shadow of 4cm long. At the same time if a building castes a shadow of 28cm. What is the heigh of building​

Answer 1

Step-by-step explanation:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90∘ both 90∘ as both are vertical to ground

∠C=∠F  (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

Answer 2

Answer:

Take help from this diagram

Step-by-step explanation:

let AB be h.

In triangle ABE and triangle CDE

angle B= angle D (90 degree)

angle E = angle E (common)

so triangle ABE ~ triangle CDE (AA)

so AB/CD = BE/DE ( corresponding parts of similar triangles)

h/6 =28/4

h =7×6

so height of building is 42 cm