Question

a straight road leads to the foot of a tower of height 50m . from the top of tower the angle of depression of two cars standing on the road are 30° and 60° what's is the distance between the two cars​

Answer 1

Answer:

57.73m

Step-by-step explanation:

A

|\\

| \ \

| \ \

|__\__\

B C D

angle ACB(C)= 60°

angle ADB (D) = 30°

AB=50 m

tanD = AB/BD tanC=AB/BC

tan30= 50/BC+CD tan60=50/BC

1/√3= 50/BC+CD √3= 50/BC

√3= BC/50 + CD/50 1/√3 =BC/50

√3= 1/√3 + CD /50 <------/

√3-1/√3= CD/50

(3-1/√3)50=CD

CD = 2*50/√3

= 100/√3

=57.73m