Question

A straight rod of length l(t), hinged at one end and freely extensible at the other end, rotates through an angle (t) about the hinge. At time t, l(t)=1m, l (t)=1m/s, (t) = 4 rad and (t) = 1 rad/s. The magnitude of the velocity at the other end of the rod is

Answer 1

The magnitude of the velocity at the other end of the rod is √ 2 m/s

Explanation:

Given data:

• Length of rod = l
• Angle of rotation = t

Now at time "t"

Length of rod = 1 m

Angle of rotation = 4 rad

Speed = 1 m/s

Solution:

Now find the magnitude of the velocity.

V = √ (1)^2 + (1)^2  = √ 2 m/s

Thus the magnitude of the velocity at the other end of the rod is √ 2 m/s.

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