A straight steel wire of length 'I' has magnetic moment 'M'. If the wire is bent in the form of a circular loop, find the new value of the magnetic dipole moment.
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Answer:
Explanation:
Length l, long wire is twisted in the state of half circle of span r, at that point, length of the wire is calculated as follows:
Circuit of the half circle (i.e., l=πr)
⟹r=
π
l
Now, attractive dipole=attractive dipole minute×least detachment between two dipoles
Least division between the dipoles is=2r=
π
2l
∴Attractive dipole=M×
π
2l
=
π
2m
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