Question

A straight steel wire of length I has magnetic moment m. If the wire is bent in the form of a semicircle, the new value of the magnetic dipole moment is(A) m
(B) 2m/π
(C) m/2
(D) m/π

Answer 1

Length L, long wire is twisted in the state of half circle of span r. at that point, length of wire = circuit of half circle L = πr

=> r = L/2π now, attractive dipole = attractive dipole minute × least detachment between two dipoles here obviously, least division between dipoles is 2r = 2L/π consequently, attractive dipole = M × 2L/π = 2ML/π.

Answer 2

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☸ Required Answer is ⬇ ⬇⬇

☯ (B). 2m/π


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