Question

A straight wire carries a current of 10 A .An electron moving at 10 ^7 m/s is at a distance 2.0 cm from the wire. Find the force acting on the electron if its velocity is directed towards the wire.​

Answer 1

Answer:

he force exerted by the magnetic field of the current electron is [/tex].

Explanation:

Given that,

Current I = 10 A

Speed

Length l = 0.1 m

We know that,

The force exerted by the magnetic field is

B = \dfrac{\mu_{0}I}{2\pi\times d}

B = \dfrac{4\pi\times10^{-7}\times 10}{2\pi\times0.1}

B = 2\times 10^{-6} T

The force will be

F = 1.6\times10^{-19}\times5\times10^{6}\times20\times10^{-6}

F = 1.6\times10^{-17}\ N

The magnetic field is

The force will be

Hence, The force exerted by the magnetic field of the current electron is .

F = 1.6\times10^{-17}\ N

Explanation: