Physics, asked by Madanmadan8000, 6 months ago

A straight wire carries a current of 3A. The magnitude of the magnetic field at a point 15cm away from the wire is

Answers

Answered by Ekaro
8

\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}

Current carried by straight wire = 3A

\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}

We have to find magnitude of the magnetic field at a point 15 cm away from the wire.

\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}

➠ Magnetic field due to an infinitely long straight conductor at a distance of R is given by

\dag\:\underline{\boxed{\bf{\purple{B=\dfrac{\mu_oI}{2\pi R}}}}}

Let's Calculate :D

:\implies\tt\:B=\dfrac{\mu_oI}{2\pi R}

:\implies\tt\:B=\dfrac{(4\pi\times 10^{-7})\times3}{2\pi\times (15\times 10^{-2})}

:\implies\tt\:B=\dfrac{6\times 10^{-5}}{15}

:\implies\boxed{\bf{\gray{B=4\times 10^{-6}\:T}}}

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