Question

A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in uniform magnetic field of induction 2 tesla. The magnetic field is perpendicular to the length of the wire. The force on the wire is(a) 2.4 N(b) 1.2 N(c) 3.0 N(d) 2.0 N

Answer 1

Answer:

1.2N

Explanation:

Length of the wire = 0.5m (Given)

Current = 1.2 ampere (Given)

Induction = 2 Tesla (Given)

Let B be the uniform magnetic field, the current in the wire of length L be I, Thus, the force due to magnetic field is given by

F = IL x B

L = 0.5m

I = 1.2 A

B = 2T

Therefore,

|F|= 1.20×0.5 ×2 × sin90

|F|= 1.20×0.5 ×2 × sin π/2

= 1.2

Therefore, if the magnetic field is perpendicular to the length of the wire, then the force on the wire is 1.2N

Answer 2

Answer:

1.2N

Explanation:

Length of the wire = 0.5m (Given)

Current = 1.2 ampere (Given)

Induction = 2 Tesla (Given)

Let B be the uniform magnetic field, the current in the wire of length L be I, Thus, the force due to magnetic field is given by

F = IL x B

L = 0.5m

I = 1.2 A

B = 2T

Therefore,

|F|= 1.20×0.5 ×2 × sin90

|F|= 1.20×0.5 ×2 × sin π/2

= 1.2

Therefore, if the magnetic field is perpendicular to the length of the wire, then the force on the wire is 1.2N