Question

A straight wire of length 0.5m and carrying a current 1.2A is placed in uniform magnetic field of induction 2T. The magnetic field is perpendicular to the length of the wire. The force on the wire is
(A)2.4N
(B)1.2N
(C)3.0N
(D)2.0N​

Answer 1

Answer:

Here, B= 2T, I= 1.2A, L=0.5m and theta = 90° as the magnetic field is perpendicular to the length of the wire. So force F = 2 × 1.2 × 0.5 ×1 N = 1.2N. ... We know that a moving charge creates magnetic field around it. Let us move together with the charge with same speed.

Answer 2

$\huge\underbrace\bold\red{AnsWer⇒}$

$F=Bilsinθ ,Here θ=900 \\ </p><p>F=2×1⋅2×0⋅5 \\ </p><p>F=1⋅2N</p><p></p><p>$

Hence option no (B) is correct.....✔️✔️