A straight wire of length 2 m carries a
current of 10 A. If this wire is placed in a
uniform magnetic field of 0.15 T making a
angle of 45° with the magnetic field, the
applied force on the wire will be
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Answer:
- straight wire of length 2 m
Explanation:
carries a
current of 10 A
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Hey!!Mate
Here is your ans:-
Explanation:
Given: i=10A,B=0.15 T,θ=45∘ and l=2 m
Force on a current carrying wire of finite length =F=l(i×B)
Hence, magnitude of force, F=Bilsinθ
=0.15×10×2×sin45∘
=23N
I hopes it helps you❤️❤️
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