Question

A straight wire of linear charge density 1 = 3 uC/m
and area of cross section A = 4 mm2 is given as
shown in figure. When wire is pulled with speed 2
m/s, then current associated with it is
do
+
+
+
+
+
+ + + +
e dL
V
(1) 2uA
- 3 6 ЦА
(2) 6 mA
(4) 4MA​

Answer 1

Answer:

6 ma is a correct answer

Answer 2

The current is 6μA.

(3) is correct option.

Explanation:

Given that,

Charge density = 3μC/m

Area cross section = 4 mm²

Speed = 2 m/s

We need to calculate the current

Using formula of rate of flow of charge

$i=\dfrac{dq}{dt}$

We know that,

$dq=\lambda dx$

Put the value of dq in the equation (I)

$i=\lambda\dfrac{dx}{dt}$

$i=\lambda\times v$

Put the value into the formula

$i=3\times 2$

$i=6\ \mu A$

Hence, The current is 6μA.

Learn more :

Topic : current density

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