Question

A straight wire of mass 200 gram and length 1.5 metre carries a current of 2 ampere it is suspended in mid air by uniform horizontal magnetic field what is the magnitude of the magnetic field

Answer 1

Mass of wire (m) = 200 grams or 0.2 kg

length (L) = 1.5 m

Current (I) = 2 A

Acceleration due to gravity (g) = 9.8 m/s^2

The weight of the wire will be balanced by the magnetic force acting in the opposite direction.

Let the magnetic field be B.

mg = ILB

$B = \frac{mg}{IL}$

$B = \frac{0.2 \times 9.8}{2 \times 1.5}$

B = 0.653 T

The value of uniform magnetic field is 0.653 T.

Answer 2

Answer:

Mass of wire (m) = 200 grams or 0.2 kg

length (L) = 1.5 m

Current (I) = 2 A

Acceleration due to gravity (g) = 9.8 m/s^2

The weight of the wire will be balanced by the magnetic force acting in the opposite direction.

Let the magnetic field be B.

mg = ILB

B = 0.653 T

The value of uniform magnetic field is 0.653 T.