Question

A straight wire of mass 200g
and length 1.5m carries a
current of 2A. It is suspended
in mid air by a uniform
horizontal magnetic field. Find
its magnitude.
1-1.657
2- 0.67T
3-16.5T
4- 165T​

Answer 1

Explanation:

3 is the correct answer

Answer 2

Answer:

Force by magnetic field = mg

Current×length×magnetic field = mg

2×1.5×B = 200×10^-3 × 10

B = 1/1.5 = 0.67T