A straight wire of mass 300 g and length 2.5 m
carries a current of 3.5 A. It is suspended in mid-air
by a uniform horizontal magnetic field B. What is the
magnitude of the magnetic field?
Answers
Answered by
2
Answer:
Given, mass of the wire =200g=0.2kg
Length of the wire =15m
Current i=2A
Magnetic field B=?
The force acting on the current carrying wire in uniform magnetic field
F=Bilsinθ
F=Bil (∵θ=90
o
)
Weight of the wire w=mg=0.2×9.8N
In the position of suspension
Bil=mg
B=
il
mg
=
2×15
0.2×9.8
=0.65T
Answered by
0
Explanation:
let, the mass of straight wire=300g=0.3kg
length=2.5 m
current=3.5 A
magnetic field B=?
The force acting on the current carrying conductor in uniform magnetic field.
mg= ILB
B=mg/il
B=0.3×9.8/3.5×2.5
B=2.1
Similar questions