Question

A stream 200metre broad is running downward at the rate of 1kmper hour.A swimmer who can swim at the rate of 2km per hour wishes to reach a point just opposite.Along what line should he striker and how long will he taken in crossing​

Answer 1

Answer:

ab ced eji168........

Answer 2

ANSWER :-

$\implies \: \boxed{ \theta \: = \tan {}^{ - 1} ( \frac{1}{2} ) = 26.56degrees}$

$\implies$He should strike along the line at an angle 26.56 degrees with vertical joining the two sides of stream.

$\implies$Resultant velocity along the line on which he travels =√1^(2) + 2^(2) .

= √5 kmph. (cos @=0)

$\implies$Time taken is ,

Time = distance/speed = 0.2/√5 hours.

$\implies \boxed{Time= 0.2/√5}$

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