a stream of electrons travelling with velocity of 6 × 10 ^9 cm / s passes between parallel plates . An electric field of 30 V/cm has been applied across the plates . calculate the strength of the magnetic field to keep the electrons undefeated.
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Answer:
Force exerted by the electric field on the electrons =1800×e
Acceleration
experienced by electrons =
m
1800e
Time taken to move 0.1m
=
3×10
7
0.1
S
=3.333×10
−9
In the above electrons deflected 2mm,
from [S=
2
1
at
2
]2×10
−3
=
2
1
×
m
1800e
×(3.333×10
−9
)
2
⇒
1800×(3.3333)
2
4×10
−3
×10
18
=
m
e
⇒
m
e
=2.0000×10
11
So,
m
e
=2×10
11
So, the answer is option (C).
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