Question

A stream of water flowing horizontally with a speed of 15 $ms^{-1}$ pushes out of tube of cross sectional area $10^{-2}\ m^{2$ and hits at a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?

Answer 1

I don't understand your question

Answer 2

Answer:

= 10^-2 m^2

# Solution-

Mass of water coming out of the pipe per second is calculated by,

dm/dt = A×v×ρ

dm/dt = 10^-2 × 15 × 1000

dm/dt = 150 kg/s

Here, water does not rebound, hence

Force = change in momentum per unit time

Force = dm/dt × v

Force = 150 × 15

Force = 2250 N

Force exerted on the wall will be 2250 N.

Explanation: