Question

A stream of water flowing horizontally with a speed of 15 ms/s gushes out of a tube of cross sectional 10^-2msq.and hits at a vertical wall nearby . what is the force exerted by the impact of water assuming that water rebounds with the same speed.

Answer = 4500N​

Answer 1

Answer:

4500 n because its rights answer is thisso u can right thus

Answer 2

Answer:

Answer:-

Speed of the water stream, v = 15 m/s

Cross-sectional area of the tube, A = 10–2 m2

Volume of water coming out from the pipe per second,

V = Av = 15 × 10–2 m3/s

Density of water, ρ = 103 kg/m3

Mass of water flowing out through the pipe per second = ρ × V = 150 kg/s

The water strikes the wall and does not rebound. Therefore, the force exerted by the water on the wall is given by Newton’s second law of motion as:

F = Rate of change of momentum = ∆P / ∆t

= mv / t

= 150 × 15 = 2250 N

Explanation:

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