Question

A street Lane is to be paved with tiles of length 12cm and breadth 10cm.if the length of the lane is 240m and it's breadth is 12m,find the number of tiles neede.

Answer 1

Area of Tiles= 12*10= 12$cm^{2}$
Area of the Lane= 240*12= 2880$m^{2}$= 2880*10000= 28800000$cm^{2}$

No. of Tiles required- Area of Lane/ Area of Tiles= 28800000/12= 24,00,000 tiles

Answer 2

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
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➧ Area of Tiles

➾ 12× 10= 12cm²

➧ Area of the Lane

➾ 240× 12 = 2880²
➾ 2880 × 10000
➾ 28800000 cm²

➧ No. of Tiles required =
Area of Lane / Area of Tiles

➾ 28800000 / 12
➾ 24,00,000 tiles ...✔

__________
Thanks...✔