Question

A street seller bought maize corns for Rs 20 per kg. In one kg there are approximately 5 heads of corns. He sells roasted corns for Rs 8 per piece. How many corns will he have to sell in order to earn a profit of Rs 200 in a day?

Answer 1

Profit from one corn head equals to 8 minus 20 upon 5 equals to 8 - 4 = 4 number of corn heads equals to 200 upon 4 equals to 50

Answer 2

Given that

Cost price of 1 kg maize corn is rs 20

Now,
Each kg had 5 heads of corns.

Now
Each corn was roasted and sold.
The selling price of the corn was rs8 per piece.
So
Selling price of 1 kg will be =
8 *5 = rs 40

Now,

Sp of 1 kg is greater than cp of 1 kg
This means there is a profit
Profit of ( 40 - 20) = rs 20 per kg

Now,

The street seller wants to make a profit of rs 200 in a day

Now
Profit on each kg is rs 20
So
Weight to be sold to earn profit of rs200 is
$= \frac{200}{20} = 10 \: kg$

This means he has to sell 10 kg in a single day to earn a profit of rs 200 each day.

Now
We already know that each kg is having 5 heads of corn
So,
Heads of corn in 10 kg is
5 * 10 = 50 heads of corns.


Therefore, the street seller should sell 50 heads of corn to earn a profit of rs200 in a day.