Question

a stress of 1 kg mm^-2 is applied to a wire of which young modulous is 10^11 Nm^-2.find the percentage increase in length. ​

Answer 1

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Answer 2

Answer:

0.0196 is the answer

Explanation:

Given:Stress=2 kg/mm

2

=2×

10

−6

9.8

Pa=19.6×10

6

Pa

Young's Modulus of elasticity Y=10

12

dyne/cm

2

Since, 1 dyne=10

−5

N

Y=10

11

N/m

2